Question 428686: joey has $4 in nickels and dimes, and he has five more nickel than dimes. How many of each coin does he have? Answer by jorel1380(3719) (Show Source):
You can put this solution on YOUR website! .05x+.10y=4
y=x-5
5x+10y=400
5x+10(x-5)=400
15x-50=400
15x=450
x=30
y=25
Joey has 30 nickels and 25 dimes..