SOLUTION: I just need help setting this up, I can solve it after that. At a Conseesion stand, five hotdog(s) and two hamburger(s) cost $9.75; two hotdog(s) and five hamburger(s) cost $11.25

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: I just need help setting this up, I can solve it after that. At a Conseesion stand, five hotdog(s) and two hamburger(s) cost $9.75; two hotdog(s) and five hamburger(s) cost $11.25      Log On


   

Question 428527: I just need help setting this up, I can solve it after that.
At a Conseesion stand, five hotdog(s) and two hamburger(s) cost $9.75; two hotdog(s) and five hamburger(s) cost $11.25, Find the cost of one hotdog and one hamburger.
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
5x+2y=9.75 .............1
2x+5y=11.25 .............2

multiply (1)by -5
Multiply (2) by 2
-25x-10y =-48.75
4x+10y=22.5
Add the two equations
-21x=-26.25
/-21
x=1.25 hotdog cost

plug value of x in (1)
5x+2y=9.75
6.25+2y= 9.75
2y=9.75 -6.25
2y=3.5
y=1.75 hamburger cost