SOLUTION: John has 300 feet of lumber to frame a rectangular patio (the perimeter of a rectangle is 2 times length plus 2 times width). He wants to maximize the area of his patio (area of a

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: John has 300 feet of lumber to frame a rectangular patio (the perimeter of a rectangle is 2 times length plus 2 times width). He wants to maximize the area of his patio (area of a       Log On


   

Question 42843: John has 300 feet of lumber to frame a rectangular patio (the perimeter of a rectangle is 2 times length plus 2 times width). He wants to maximize the area of his patio (area of a rectangle is length times width). What should the dimensions of the patio be, and show how the maximum area of the patio is calculated from the algebraic equation.
*Show clearly the algebraic steps which prove your dimensions are the maximum area which can be obtained.
Answer by psbhowmick(878) About Me  (Show Source):
You can put this solution on YOUR website!
Why are you asking the same question so many time?
If you can't understand a particular step then ask the tutor, who solved the problem, about that particular step instead of repeating your question.

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