SOLUTION: Soybean meal is 12% protein, cornmeal is 6% protein, how many pounds of each should be mixed together in order to get 240 pound mixture that is 10% protein? I have tried to solv

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Question 428387: Soybean meal is 12% protein, cornmeal is 6% protein, how many pounds of each should be mixed together in order to get 240 pound mixture that is 10% protein?
I have tried to solve this at least a dozen times and only get part of it right.
Can you please explain how?

Found 2 solutions by stanbon, htmentor:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Soybean meal is 12% protein, cornmeal is 6% protein, how many pounds of each should be mixed together in order to get 240 pound mixture that is 10% protein?
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Equation:
protein + protein = protein
0.12x + 0.06(240-x) = 0.10*240
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Multiply thru by 100 to get:
12x + 6*240-6x = 10*240
6x = 4*240
x = (2/3)*240
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x = 160 lbs. (amt of Soybean needed)
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240-x = 80 lbs. (amt of Cornmenal needed)
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Cheers,
Stan H.
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Answer by htmentor(1343) About Me  (Show Source):
You can put this solution on YOUR website!
Let x = the number of pounds of soybean meal
Then 240-x = the number of pounds of cornmeal
Then we can write:
0.12x + 0.06(240-x) = 0.10*240
0.06x = 9.6 -> x = 160
So 160 pounds soybean, 80 pounds cornmeal
Check:
0.12*160 = 19.2
0.06*80 = 4.8
Total protein = 19.2 + 4.8 = 24 pounds out of 240 pound mixture = 10% protein