SOLUTION: please help me find the vertices, center, and asymptotes of the hyperbola (x-4)^2/3^2-(y-2)^2/2^2
Algebra
->
Quadratic-relations-and-conic-sections
-> SOLUTION: please help me find the vertices, center, and asymptotes of the hyperbola (x-4)^2/3^2-(y-2)^2/2^2
Log On
Algebra: Conic sections - ellipse, parabola, hyperbola
Section
Solvers
Solvers
Lessons
Lessons
Answers archive
Answers
Click here to see ALL problems on Quadratic-relations-and-conic-sections
Question 428006
:
please help me find the vertices, center, and asymptotes of the hyperbola
(x-4)^2/3^2-(y-2)^2/2^2
Found 2 solutions by
Gogonati, poliphob3.14
:
Answer by
Gogonati(855)
(
Show Source
):
You can
put this solution on YOUR website!
Solution:The center of hyperbola is: (x-4=0 => x=4 and y-2=0 => y=2), (4,2)
The vertices are: (-3,0) and (3,0)
The asymptotes are: y=+/-(b/a)x=+/-(2/3)x
and
Answer by
poliphob3.14(115)
(
Show Source
):
You can
put this solution on YOUR website!
Solution:The center of hyperbola is (4,2)
The vertices are:(7,2) and (1,2)
The asymptotes are:
and