Question 427964: Find three consecutive even integers
such that twice the smallest plus three
times the largest will result
in the middle integer plus 98. Answer by John10(297) (Show Source):
You can put this solution on YOUR website! Let x be the smallest even number then x + 2 and x + 4 are the second and third even numbers respectively.
The sum of twice of smallest number and three times of the largest number is equal to the sum of second number plus 98
2x + 3(x+4) = (x+2)+ 98
2x + 3x + 12 = x + 100
4x = 88
x = 22
Thus the smallest number is 22
the middle number is 24
the largest number is 26
Let me know if you have any question! John10