Question 427710: A researcher collected sample data for 12 women ages 18 to 24. The sample had a mean serum cholesterol level (measured in mg/100 mL) of 189.9 , with a standard deviation of 5.5. Assuming that serum cholesterol levels for women ages 18 to 24 are normally distributed, find a 99% confidence interval for the mean serum cholesterol level of all women in this age group.
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! A researcher collected sample data for 12 women ages 18 to 24.
The sample had a mean serum cholesterol level (measured in mg/100 mL) of 189.9 , with a standard deviation of 5.5.
Assuming that serum cholesterol levels for women ages 18 to 24 are normally distributed, find a 99% confidence interval for the mean serum cholesterol level of all women in this age group.
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x-bar = 189.9
ME = 2.5758*5.5/sqrt(12) = 4.40897
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99%CI: 189.9-4.40897 < u < 189.9+4.40897
99%CI: 185.81 < u < 194.30897
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Cheers,
Stan H.
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