SOLUTION: I need help could someone please explain this to me? the equation of the line that is perpendicular to the graph of y=1/3x-4; passing through (0,-1)

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: I need help could someone please explain this to me? the equation of the line that is perpendicular to the graph of y=1/3x-4; passing through (0,-1)      Log On


   

Question 427670: I need help could someone please explain this to me?
the equation of the line that is perpendicular to the graph of y=1/3x-4; passing through (0,-1)
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi

Using the standard slope-intercept form for an equation of a line y = mx + b

  where m is the slope and b the y-intercept. 

 y=1/3x-4  |Slope m = (1/3) AND the slope of a line perpendicular to it is -3/1

 Perpendicular Lines have slopes that are negative reciproclas of one another.

New Line:

 y = -3x + b    |using Pt(0,1) to solve for b

 1 = -3*0 + b

 1 = b   EQ of this line is y = -3x+1