SOLUTION: Ok again I am stumped by this ; Write the slope-intercept equation for the line that passes through (-8, -11) and is perpendicular to -2x – 7y = -14
I tried this -2-8.37=10.37
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-> SOLUTION: Ok again I am stumped by this ; Write the slope-intercept equation for the line that passes through (-8, -11) and is perpendicular to -2x – 7y = -14
I tried this -2-8.37=10.37
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Question 427584: Ok again I am stumped by this ; Write the slope-intercept equation for the line that passes through (-8, -11) and is perpendicular to -2x – 7y = -14
I tried this -2-8.37=10.37
-1-7.07=-8.07
=1.29
???????? Have I totally did this wrong? Found 2 solutions by mananth, lwsshak3:Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! -2x-7y=-14
Find the slope of this line
-7y=2x+14
Divide by -7
y=- 2/7 x-2
Compare this equation with y=mx+b
slope m =-0.29
The slope of a line perpendicular to the above line will be the negative reciprocal
m1*m2=-1
The slope of the required line will be 3.50 3.5 =
m= 3.50 ,point (-8,-11)
Find b by plugging the values of m & the point in
y=mx+b
-11=-28+ b
b=17
m=3.5
The required equation is y=3.5x +17
You can put this solution on YOUR website! Ok again I am stumped by this ; Write the slope-intercept equation for the line that passes through (-8, -11) and is perpendicular to -2x – 7y = -14
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-2x-7y=-14
convert to standard form, y=mx+b, m=slope and b=y-intercept
7y=-2x+14
y=(-2/7)x+2
slope =-2/7
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slope of equation perpendicular to first equation is equal to its negative reciprocal=7/2
Equation:
y=mx+b
using point (-8,-11) to solve for b
-8=(7/2)(11)+b
-16=77+2b
-93=2b
b=93/2
Equation of line:
y=(7/2)x+93/2 (ans)
see graph of these two lines below:Note the slopes of the two lines
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