|
Question 427425: Write the slope-intercept equation for the line that passes through (-12, 10) and is perpendicular to 4x + 6y = 3
Answer by John10(297)   (Show Source):
You can put this solution on YOUR website! Write the slope-intercept equation for the line that passes through (-12, 10) and is perpendicular to 4x + 6y = 3
--------------------------
First find the slope of the given line:
Write the equation i slope-intercept form: y = mx + b
4x + 6y = 3
6y = -4x + 3
y = (-2/3)x + 1/2
Since the given line is perpendicular with the new line, their slopes product is -1.
Let m be the slope of the new line: (-2/3)m = -1
m = -1 * (-3/2) = 3/2
Now we use the slope m = 3/2 and (-12, 10) to find the equation
y -10 = 3/2 (x +12)
y -10 = (3/2)x + 18
y = (3/2)x + 28
This is the line that we need to find!Hope it will help you!
|
|
|
| |
