SOLUTION: find all the REAL zeros of the function x^4-4x^3+4x-1

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Question 427338: find all the REAL zeros of the function x^4-4x^3+4x-1
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi

 x^4-4x^3+4x-1 = 0    |If x=1 then 1-4+4-1 = 0 (x-1) a factor

dividing the above by (x-1)

x^3 - 3x^2 - 3x + 1    |If x= -1 then -1-3+3+1 = 0 (x+1) a factor

dividing the above by (x+1)

x^2 - 4x + 1

x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+

x+=+%28-4+%2B-+sqrt%28+12+%29%29%2F%282%29+

x+=+%28-4+%2B-+2sqrt%28+3+%29%29%2F%282%29+

x+=+-2+%2B-+sqrt%28+3+%29

all the REAL zeros of the function:

 {-3.7321,-1, -.2679, 1 }