SOLUTION: A rectangle's length is 4 more than 4 times the width. The perimeter is 88 feet. What is the length and width of the rectangle? Use variables to label the rectangle. then show
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Question 427318: A rectangle's length is 4 more than 4 times the width. The perimeter is 88 feet. What is the length and width of the rectangle? Use variables to label the rectangle. then show your work for checking your answer. Answer by algebrahouse.com(1659) (Show Source):
You can put this solution on YOUR website! "A rectangle's length is 4 more than 4 times the width. The perimeter is 88 feet. What is the length and width of the rectangle? Use variables to label the rectangle. then show your work for checking your answer."
x = width
4x + 4 = length {length is 4 more than 4 times width}
Perimeter of a rectangle = 2(width) + 2(length)
2x + 2(4x + 4) = 88 {perimeter is 2(width) + 2(length)}
2x + 8x + 8 = 88 {used distributive property}
10x + 8 = 88 {combined like terms}
10x = 80 {subtracted 8 from both sides}
x = 8 {divided both sides by 10}
4x + 4 = 36 {substituted 8, in for x, into 4x + 4}
width = 8
length = 36
Perimeter of a rectangle
= 2(width) + 2(length)
= 2(8) + 2(36)
= 16 + 72
= 88 www.algebrahouse.com
