SOLUTION: A hiker begins a 25 km(point B) hike from point A at 7am travelling at a rate of 4km per hour. At 9:30, a bike rider leaves point B travelling at a rate of 16 km per hour. What t
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Question 427284: A hiker begins a 25 km(point B) hike from point A at 7am travelling at a rate of 4km per hour. At 9:30, a bike rider leaves point B travelling at a rate of 16 km per hour. What time will the hiker and biker cross paths (meet)? At what kilometer will they meet? Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! Hiker 4 km/h
Biker 16 km/h 2.5 hours late
Distance 25 miles
In 2.5 hours Hiker has traveled 10 miles before Biker starts
So distance = 15 when Biker starts
Let time they meet be x hours
Hiker distance traveled 4x miles
Biker distance traveled 16(15 -x)
Time taken to meet is same
t=d/r
combined speed= 20 mph
20x=15
x= 0.75 hours
Hiker 4x=3 miles
Hiker would have traveled 3+10=13 miles
Biker (25-13)=12 miles
They will cross at 10:15 AM
