SOLUTION: How do you find the coordinates of the center and foci and the lengths of the major and minor axes for the ellipse whose equation is given 4x^2 + 8y^2 = 32

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Question 427115: How do you find the coordinates of the center and foci and the lengths of the major and minor axes for the ellipse whose equation is given 4x^2 + 8y^2 = 32
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi

Ellipse:

4x^2 + 8y^2 = 32 

x%5E2%2F8+%2B+y%5E2%2F4+=+1

 Standard Form of an Equation of an Ellipse is %28x-h%29%5E2%2Fa%5E2+%2B+%28y-k%29%5E2%2Fb%5E2+=+1+where Pt(h,k) is the center

 and a and b  are the respective vertices.. Distances from center.

Center is (0,0)

Vertices:  (sqrt(8),0) and (-sqrt(8),0)  AND (0,2) and (0-2)

foci: (2,0) and (-2,0)    c = sqrt%288-4%29+=+2

length of major axis is : 2sqrt(8)

length of minor axis is : 2*2 = 4