SOLUTION: solve the system of equations using the addition method. equ 1: 2x-1/5y=-5 equ 2: 3x-5/2y=-37/2 I have tried tried multiplying -5 to (equ 1) to take out the fraction and a

Algebra ->  Rational-functions -> SOLUTION: solve the system of equations using the addition method. equ 1: 2x-1/5y=-5 equ 2: 3x-5/2y=-37/2 I have tried tried multiplying -5 to (equ 1) to take out the fraction and a      Log On


   

Question 427063: solve the system of equations using the addition method.
equ 1: 2x-1/5y=-5
equ 2: 3x-5/2y=-37/2
I have tried tried multiplying -5 to (equ 1) to take out the fraction and
and -2 to (equ 2) and I'm not sure if that's correct so far.
Answer: equ 1: 10x+y=25
equ 2: 6xt10y=74
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi, 

would like to accomplish eliminating the y-terms in one step:

solve the system of equations using the addition method.

 2x-(1/5)y=-5

 3x-(5/2)y=-37/2



 -25x +(5/2)y = 125/2  |Mulitplying 1st EQ by -25/2 Note: %28-25%2Fcross%282%29%29+%2Across%282%29x+= -25x

  3x  -(5/2)y = -37/2

       -22x = 88/2 = 44

         x = -2  and y = (2x+5)5 = 5

Ordered pair (-2,5) the solution for this system



CHECKING our Answer***

 3x -(5/2)y= -37/2

 -6 - 25/2 =  -12/2 - 25/2 = -37/2