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Question 426967: find 4 consecutive numbers whose sum is 15 less than 5 times the first.
Answer by htmentor(1343)   (Show Source):
You can put this solution on YOUR website! Let x = the (first) lowest number
Then the other numbers are x+1, x+2 and x+3
Given: sum is less than 5 times the first.
In equation form this is:
x + x+1 + x+2 + x+3 = 5x - 15
Now collect terms and solve for x:
4x + 6 = 5x - 15 -> x = 21
So the 4 numbers are:
21, 22, 23, 24
Check:
21 + 22 + 23 + 24 = 90
5(21) = 105
105 - 90 = 15, so sum is 15 less than 5 times the first
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