SOLUTION: If the area if a rectangle is 143 sq feet and the perimeter is 48 feet, what are the dimensions?
Algebra
->
Rectangles
-> SOLUTION: If the area if a rectangle is 143 sq feet and the perimeter is 48 feet, what are the dimensions?
Log On
Geometry: Rectangles
Geometry
Solvers
Solvers
Lessons
Lessons
Answers archive
Answers
Click here to see ALL problems on Rectangles
Question 426907
:
If the area if a rectangle is 143 sq feet and the perimeter is 48 feet, what are the dimensions?
Answer by
edjones(8007)
(
Show Source
):
You can
put this solution on YOUR website!
Lw=A, 2(L+w)=P
Lw=143
2(L+w)=48
L+w=24
L=24-w
w(24-w)=143
-w^2+24w=143
w^2-24w=-143
w^2-24w+143=0
(w-13)(w-11)=0
w=11, L=13 or vice versa.
.
Ed