SOLUTION: How many pounds of chamomile tea that cost $4.50 per pound must be mixed with 11 lb of orange tea that cost $2.80 per pound to make a mixture that cost $3.82 per pound? Round to th
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Question 426895: How many pounds of chamomile tea that cost $4.50 per pound must be mixed with 11 lb of orange tea that cost $2.80 per pound to make a mixture that cost $3.82 per pound? Round to the nearest decimal Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! How many pounds of chamomile tea that cost $4.50 per pound must be mixed with 11 lb of orange tea that cost $2.80 per pound to make a mixture that cost $3.82 per pound? Round to the nearest decimal
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Value: 4.5c + 2.8*11 = 3.82(c+11)
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Multiply thru by 100 to get:
450c + 280*11 = 382c + 382*11
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68c = 102*11
c = 19.34 lbs of chamomile tean needed
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Cheers,
Stan H.
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