SOLUTION: ln 2x-ln(x-2)=ln3
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Question 426814
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ln 2x-ln(x-2)=ln3
Answer by
lwsshak3(11628)
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ln 2x-ln(x-2)=ln3
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ln2x-ln(x-2)=ln3
=ln2x-ln(x-2)-ln3=0
=ln2x-(ln(x-2)+ln3)=0
ln(2x/(3(x-2))=0
convert to exponential form,
e^0=(2x/(3(x-2))=1
=2x/3x-6=1
2x=3x-6
x=6 (ans)