SOLUTION: The sum of three integers is 61. The sum of the first and second integers exceeds the third by 81. The third integer is 20 less than the first. Find the three integers.

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Question 426619: The sum of three integers is 61. The sum of the first and second integers exceeds the third by 81. The third integer is 20 less than the first. Find the three integers.
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi

third integer is 20 less than the first; sum of three integers is 61

Let x, [61 -(x + (x-20))], (x-20) represent the 1st, 2nd and 3rd integer respectiveely

Question states***

 x + [61 -(x + (x-20))] = (x-20) + 81

Solving for x

 x + [61 -(2x-20)]= x+61

       20 = 2x

        x = 10, first Integer.  2nd = 61    3rd = -10  (x-20)



CHECKING our Answer***

  10 +61 = -10 + 81 = 71