SOLUTION: find the standard form of the equation 196x^2+9y^2+392x+54y-1487=0 by completing the square, identify and graph the conic section

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: find the standard form of the equation 196x^2+9y^2+392x+54y-1487=0 by completing the square, identify and graph the conic section       Log On


   

Question 426567: find the standard form of the equation 196x^2+9y^2+392x+54y-1487=0 by completing the square, identify and graph the conic section
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi

find the standard form of the equation by completing the square

196x^2+9y^2+392x+54y-1487=0

 196(x+1)^2 -196 + 9(y+3)^2 -81 - 1487 = 0

  196(x+1)^2  + 9(y+3)^2 = 1764

  (x+1)^2/9  + 9(y+3)^2/196 = 1

 +%28x%2B1%29%5E2%2F3%5E2++%2B+9%28y%2B3%29%5E2%2F14%5E2+=+1

Elipse: a = 3 and b = 14  C(-1,-3)