SOLUTION: What is the standard form of 9x^2- 16y^2 -18x + 96y - 279=0

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Question 426088: What is the standard form of 9x^2- 16y^2 -18x + 96y - 279=0
Answer by ewatrrr(24785) About Me  (Show Source):
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Hi

standard form of  

9x^2- 16y^2 - 18x + 96y - 279=0    |Note use of ^ (uppercase 6)

 9[(x-1)^2 -1] -16(y-3)^2]-9] - 279 = 0

 9(x-1)^2 - 9 -16(y-3)^2 + 144 - 279 = 0

 9(x-1)^2-16(y-3)^2 = 144

 %28x-1%29%5E2%2F16+-+%28y-3%29%5E2%2F9+=+1