SOLUTION: Factor completely: 81a^4-81b^4

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Question 425652: Factor completely:
81a^4-81b^4
Found 2 solutions by dnanos, lwsshak3:
Answer by dnanos(83) About Me  (Show Source):
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Factor completely:
81a^4-81b^4
difference of two squares:
=(9+a^2+9b^2)(9+a^2-9b^2)
=(9+a^2+9b^2)(3a+3b)(3a-3b)