SOLUTION: The length of a rectangle is 2 cm more than twice its width. If the perimeter of the rectangle is 52 cm, find the dimensions of the rectangle. let the width of the rectangle is

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: The length of a rectangle is 2 cm more than twice its width. If the perimeter of the rectangle is 52 cm, find the dimensions of the rectangle. let the width of the rectangle is      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 42524: The length of a rectangle is 2 cm more than twice its width. If the perimeter of the rectangle is 52 cm, find the dimensions of the rectangle.
let the width of the rectangle is x cm
then length of the rectangle will be 2x+2
given perimeter of the rectangle is 52 cm
=>2*(x+(2x+2))=52
=>2*(3x+2)=52
=>3x+2=26
=>3x=24
=>x=8
hence lenghth of the rectangle is 18cm and width is 8cm

Found 2 solutions by Nate, pallavi:
Answer by Nate(3500) About Me  (Show Source):
You can put this solution on YOUR website!
width = w
length = 2w + 2
2l+%2B+2w+=+p
2%282w+%2B+2%29+%2B+2%28w%29+=+52
4w+%2B+4+%2B+2w+=+52
6w+=+48
w+=+8
width = 8
length = 2w + 2 = 2(8) + 2 = 18

Answer by pallavi(12) About Me  (Show Source):