SOLUTION: michael found 36 coins. 1/4 of them were pennies, 1/3 of them were nickles,1/6 of them were quarters, and the rest were dimes. tell how many of each coin micheal found. ____ p

Algebra ->  Functions -> SOLUTION: michael found 36 coins. 1/4 of them were pennies, 1/3 of them were nickles,1/6 of them were quarters, and the rest were dimes. tell how many of each coin micheal found. ____ p      Log On


   



Question 425119: michael found 36 coins. 1/4 of them were pennies, 1/3 of them were nickles,1/6 of them were quarters, and the rest were dimes.
tell how many of each coin micheal found.
____ pennies
____ nickles
____quarters
____dimes
2. explain how you found the number of quarters?
3. how much are the coins worth all together ?

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
michael found 36 coins. 1/4 of them were pennies, 1/3 of them were nickles,1/6 of them were quarters, and the rest were dimes.
tell how many of each coin micheal found.
-----------------
Equations:
p + n + q + d = 36
--
p = (1/4)36 = 9 (# of pennies)
---
n = (1/3)36 = 12 (# of nickels)
---
q = (1/6)36 = 6 (# of quarters)
---
d = 36-(9+12+6) = 9 (# of dimes)
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Cheers,
Stan H.
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____ pennies
____ nickles
____quarters
____dimes