SOLUTION: The length of one of the equal legs of an isosceles triangle is 8 cm less than 4 times the length of the base. If the perimeter is 29 cm, find the length of one of the equal legs.

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Question 42511: The length of one of the equal legs of an isosceles triangle is 8 cm less than 4 times the length of the base. If the perimeter is 29 cm, find the length of one of the equal legs.
I believe it is 11cm.Am I right?
Answer by Nate(3500) About Me  (Show Source):
You can put this solution on YOUR website!
Base length = b
Equal leg length = 4b - 8
%28side%29+%2B+%28side%29+%2B+%28side%29+=+Perimeter
%284b+-+8%29+%2B+%284b+-+8%29+%2B+%28b%29+=+29
9b+-+16+=+29
9b+=+45
b+=+5
Equal leg length = 4b+-+8
4%285%29+-+8
20+-+8
12