SOLUTION: The perimeter of a rectangle is 66m. The length of the rectangle is 1m more than three the width. Find the dimensions of the rectangle
Algebra ->
Test
-> SOLUTION: The perimeter of a rectangle is 66m. The length of the rectangle is 1m more than three the width. Find the dimensions of the rectangle
Log On
Question 424820: The perimeter of a rectangle is 66m. The length of the rectangle is 1m more than three the width. Find the dimensions of the rectangle Found 2 solutions by Adrish, linh117:Answer by Adrish(44) (Show Source):
You can put this solution on YOUR website! Solutions:
Let the Width be "x"
Then the rectangle will be 1+3x
Given: Perimeter= 66m
We Know P= 2L + 2W
66= 2( 1+3x) + 2x
66= 2+6x+2x
66-2= 2-2 +8x
64= 8x
x=64/8
x=8m
Therefore the Length= 1+3(8)
= 25m
Width= 8m
You can put this solution on YOUR website! 66 = 2(l+w)
l = 3w + 1
plug l in formula and solve
66= 2[(3w+1)+w]
66= 2(4w+1)
66= 8w +2
64=8w
w=8
l= 3(8) +1
l=24 +1
l=25
(