SOLUTION: A chemist needs to produce a 40% acid mixture. She has 25% strength solution and 80% strength solution on hand.
Rouding to the nearest thousandth (3 decimal places; nearest mL),
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Rouding to the nearest thousandth (3 decimal places; nearest mL),
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Question 424536: A chemist needs to produce a 40% acid mixture. She has 25% strength solution and 80% strength solution on hand.
Rouding to the nearest thousandth (3 decimal places; nearest mL), how much 25% solution does she add to create 1 liter of the 40% strength mixture? Answer by jorel1380(3719) (Show Source):
You can put this solution on YOUR website! 1 litre x .4=.4
m+n=1
.25m+.8n=.4
25m+80n=40
25m+25n=25
55n=15
n=15/55=3/11
m=8/11
The chemist need 8/11ths liter of 25% solution and 3/11ths liter of 80% solution for his mix..
