SOLUTION: one canned juice drink is 20% orange juice another is 5% orange juice. how many liters of each should be mixed together in order to get 15 liters that is 16% orange juice? Please

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Question 424448: one canned juice drink is 20% orange juice another is 5% orange juice. how many liters of each should be mixed together in order to get 15 liters that is 16% orange juice?
Please help I am so confused!!
Found 2 solutions by stanbon, nerdybill:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
one canned juice drink is 20% orange juice another is 5% orange juice. how many liters of each should be mixed together in order to get 15 liters that is 16% orange juice?
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Using 2 Equations:
Quantity::: t + f = 15 liters
Juice:::0.20t + 0.05f = 0.16*15 liters
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Multiply thru the 1st eq. by 5
Multiply thru the 2nd eq. by 100
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5t + 5f = 5*15
20t + 5f = 16*15
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Subtract and solve for "t":
15t = 11*15
t = 11 liters (amt. of 20% juice needed)
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Solve for "f":
t + f = 15
11 +f = 15
f = 4 liters (amt. of 5 % juice needed)
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Cheers,
Stan H.
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Answer by nerdybill(7384) About Me  (Show Source):
You can put this solution on YOUR website!
one canned juice drink is 20% orange juice another is 5% orange juice. how many liters of each should be mixed together in order to get 15 liters that is 16% orange juice?
.
Let x = amount (liters) of 20% OJ
then
15-x = amount (liters) of 5% OJ
.
.20x + .05(15-x) = .16(15)
.20x + .75 - .05x = 2.4
.15x + .75 = 2.4
.15x = 1.65
x = 11 liters (20% OJ)
.
5% OJ:
15-x = 15-11 = 4 liters