Question 424162: If 1 gallon of anti-freeze is 80% and 60 gallon is 25%, how many gallon of the 80% do you mix with the 25% to equal 70%? Answer by ewatrrr(24785) (Show Source):
Hi
Let x represent the number of gallon of the 80% needed
Mixing to make the 70% solution
.80x + .25*60gal = .70(60gal+x)
.10x = .45*60gal
x = 270 gal
CHECKING our Answer***
.80*270 + .25*60 = .70(330) = 231