SOLUTION: Suppose X is a normally distributed random variable with the mean=10.1 and standard deviation=3.6. Find each of the following probabilities: P(10.1<=x<=15.6) and P(x>=8)

Algebra ->  Probability-and-statistics -> SOLUTION: Suppose X is a normally distributed random variable with the mean=10.1 and standard deviation=3.6. Find each of the following probabilities: P(10.1<=x<=15.6) and P(x>=8)       Log On


   

Question 424083: Suppose X is a normally distributed random variable with the mean=10.1 and standard deviation=3.6. Find each of the following probabilities:
P(10.1<=x<=15.6)
and
P(x>=8)
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Suppose X is a normally distributed random variable with the mean=10.1 and standard deviation=3.6.
Find each of the following probabilities:
P(10.1<=x<=15.6)
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z(10.1) = (10.1-10.1)/3.6 = 0
z(15.6) = (15.6-10.1)/3.6 = 5.5/3.6 = 1.5278
---
P(10.1 <= x <= 15.6) = P(0<= z <=1.5278) = 0.4367
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and
P(x>=8)
z(8) = (8-10.1)/3.6 = -0.58333
P(x >= 8) = P(z >= -0.58333) = 0.7202
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Cheers,
Stan H.
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