SOLUTION: 3+log2(x-3)=log2 4x
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Question 423993
:
3+log2(x-3)=log2 4x
Answer by
stanbon(75887)
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3+log2(x-3)=log2 4x
-----
log2(4x)-log2(x-3) = 3
----
log2[(4x)/(x-3)] = 3
----
4x/x-3 = 2^3
----
4x = 8(x-3)
4x-8x= -24
-4x = -24
x = 6
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Cheers,
Stan H.
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