Question 423992: A launched rocket has an altitude in meters, given by the polynomial h+vt-4.9^2, h is the height in meters v is the velocity in meters per second and t is the number of seconds for which it takes the rocket to become airborne. If the rocket is launched from the top of a tower that is 120 meters and the initial speed is 40 meters per second, what will its height be after 3 seconds??
the height will be __meters?
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! A launched rocket has an altitude in meters, given by the polynomial
h(t)= -4.9t^2 + vot + so, h is the height in meters vo is the velocity in meters per second, so is the initial height of the object and t is the number of seconds the rocket is airborne.
If the rocket is launched from the top of a tower that is 120 meters and the initial speed is 40 meters per second, what will its height be after 3 seconds??
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h(3) = -4.9(3)^2+40(3) + 120
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h(3) = 195.9 meters
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Cheers,
Stan H.
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