Question 423982: A launched rocket has an altitude, in meters, given by the polynomial h+vt-4.9^2, where h is the height, in meters, from which the launch occurs, at velocity v meters per second, and t is the number of seconds for which the rocket is airborne. If a rocket is launched from the top of a tower 100 meters high with an initial upward speed of 20 meters per second, what will its height be after 2 seconds.
Its height will be__meters?
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! A launched rocket has an altitude, in meters, given by the polynomial h+vt-4.9^2, where h is the height, in meters, from which the launch occurs, at velocity v meters per second, and t is the number of seconds for which the rocket is airborne. If a rocket is launched from the top of a tower 100 meters high with an initial upward speed of 20 meters per second, what will its height be after 2 seconds.
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I think it's h(t) = h + vt - 4.9t^2
h(2) = 100 + 20*2 - 4.9*4
h(2) = 120.6 meters
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PS This is not a rocket, rockets have thrust and don't fall ballistically.
This is just a projectile that is launched and has no power of its own.
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