SOLUTION: Solve this equation exactly for x (ok to leave in ln or log form). log(x)+log(2x)=2

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Question 423933: Solve this equation exactly for x (ok to leave in ln or log form).
log(x)+log(2x)=2
Found 2 solutions by linht117, MathLover1:
Answer by linht117(37) (Show Source):
You can put this solution on YOUR website!
log(x)+log(2x)=2
log(x)(2x)=2
log(2x^2)=2
let both sides be the exponent of base 10
10^log(2x^2)=10^2
exponent is release
2x^2=10^2
divide by 2
2x^2/2=100/2
x^2=100/2
square root both sides
x=+- sqrt50

Answer by MathLover1(20850) (Show Source):
You can put this solution on YOUR website!
first some basic rules to remember:
Log Rules:
1)
2)
3)

you have:
.....so, use the rule number 1

.......I assume the base is ...By the definition of the logarithm implies