Question 423910: PROBLEM:
The integer 48 is to be expressed as a sum of x consecutive odd integers. The value of x could be which of the following?
I. 2
II. 4
III. 6
a. I only
b. II only
c. I and II only
d. II and III only
e. I, II and III only
MY QUESTION:
**HOW DO I SOLVE THIS?**
Answer by sudhanshu_kmr(1152)   (Show Source):
You can put this solution on YOUR website! consecutive odd integers are x, x+2, x+4, x+6, x+8, x+10 ....
I 2 .
For 2 consecutive odd integers, the quotient of (48-2)/2 must be an odd integer.
II 4
(2 + 4 + 6 =12)
For 4 consecutive odd integers, the quotient of (48 - 12)/4 must be an odd integer.
III 6
( 2+4+6+8+10= 30)
for 6 consecutive odd integers, the quotient of (48-30)/6 must be an odd integer.
Here all conditions are satisfied.
so, answer is e.
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