SOLUTION: Write an equation of a hyperbola with vertices (3 - sqrt[2], 4) and (3 + sqrt[2], 4) and foci (3 - sqrt[10], 4) and (3 + sqrt[10], 4).

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Write an equation of a hyperbola with vertices (3 - sqrt[2], 4) and (3 + sqrt[2], 4) and foci (3 - sqrt[10], 4) and (3 + sqrt[10], 4).      Log On


   

Question 423828: Write an equation of a hyperbola with vertices (3 - sqrt[2], 4) and (3 + sqrt[2], 4) and foci (3 - sqrt[10], 4) and (3 + sqrt[10], 4).
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
Standard Form of an Equation of an Hyperbola is %28x-h%29%5E2%2Fa%5E2+-+%28y-k%29%5E2%2Fb%5E2+=+1 where Pt(h,k) is a center with vertices 'a' units right and left of center.
Write an equation of a hyperbola with vertices (3 - sqrt[2], 4) and (3 + sqrt[2], 4)
and foci (3 - sqrt[10], 4) and (3 + sqrt[10], 4)
Center (3,4) a = 2 and sqrt%28a%5E2+%2B+b%5E2%29+=+sqrt%2810%29 b^2 = 8
%28x-3%29%5E2%2F2+-%28y-4%29%5E2%2F8+=+1