Question 423242: what are the x and y intercepts of the line defined by -8x + 6y = -48 Found 2 solutions by rfer, oberobic:Answer by rfer(16322) (Show Source):
You can put this solution on YOUR website! First, get the equation into slope-intercept form.
-8x +6y = -48
Add 8x to both sides.
6y = 8x -48
Divide both sides by 6
y = (8/6)x - 8
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The x-intercept is where y=0, so substitute y=0.
0 = (8/6)x - 8
Add 8 to both sides.
8 = (8/6)x
(8/6)x = 8
Multiply both sides by 6.
8x = 48
Divide both sides by 8
x = 6
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So the x=intercept is (6,0).
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The y-intercept is where x=0.
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y = (8/6)x - 8
Substitute x=0
y = -8
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So the y-intercept is (0,-8).
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Always check your answer.
In this case a graph is useful.
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Looks good.
Done.
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