SOLUTION: Could someone please help me with 8th grade algebra? solve the linear system using substitution.
x=16-4y
3x+4y=8
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x=16-4y
3x+4y=8
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You can put this solution on YOUR website! solve the linear system using substitution.
x=16-4y
3x+4y=8
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The 1st equation tells you x = 16-4y
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Substitute that into the 2nd equation
and solve for "y":
3(16-4y)+4y = 8
48 - 12y + 4y = 8
-8y = -40
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y = 5
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Solve for "x"
x = 16-4y
x = 16-4*5
x = 16-20
x = -4
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Solution: (-4,5)
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Cheers,
Stan H.
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