SOLUTION: There are 90 ml of pure alcohol in a bottle of 750 ml of water and alcohol mixture .Find the amount of pure alcohol that must be added to obtain a new mixture that is 33% alcohol.
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Question 423025: There are 90 ml of pure alcohol in a bottle of 750 ml of water and alcohol mixture .Find the amount of pure alcohol that must be added to obtain a new mixture that is 33% alcohol. Answer by jorel1380(3719) (Show Source):
You can put this solution on YOUR website! 90/750=12%
750(.12)+n(1.00)=.33(750+n)
90+n=247.5+.33n
.66n=157.5
n=157.5/.66=238.6363
You need 238.6363 ml of pure alcohol for your mix..
