Question 422882: The sum of three numbers is 44. The second is three times the first and the third is 6 less than the first. find the numbers.
Found 2 solutions by rapaljer, htmentor:
Answer by rapaljer(4671)   (Show Source):
You can put this solution on YOUR website! Let x = the first number
3x = second number
x-6= third number
The equation is based upon the SUM of the numbers:
x+ 3x + x-6 = 44
5x - 6 = 44
5x= 50
x=10
x=10 First Number
3x= 3*10=30 Second Number
x-6=4 Third Number
Check: The sum of the numbers is 10 + 30 + 4 = 44 It checks!!
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Dr. R^2
Dr. Robert J. Rapalje
Seminole State College of Florida
Answer by htmentor(1343)  (Show Source):
You can put this solution on YOUR website! 1) x + y + z = 44
2) y = 3x
3) z = x - 6
Substitute the value of y in 2) into equation 1):
x + 3x + z = 44 -> 4x + z = 44
Solve above equation for z in terms of x:
z = 44 - 4x
Substitute the above value for z into equation 3):
44 - 4x = x - 6 -> 5x = 50 -> x = 10
Therefore, from 2), y = 3*10 = 30
And finally, from 3) z = 10 - 6 -> z = 4
Ans: x=10,y=30,z=4
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