SOLUTION: the digits 1, 2, 3, 4, 5, and 7 are randomly arranged to form a six-digit number. Find the probability that the first and last digits are both even.
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Question 422870: the digits 1, 2, 3, 4, 5, and 7 are randomly arranged to form a six-digit number. Find the probability that the first and last digits are both even. Answer by sudhanshu_kmr(1152) (Show Source):
no. of ways to arrange 6 digits where first and last digit are even
= no. of ways to arrange first and last digit * no. of ways to arrange 4 inner digits
= 2! * 4!
= 2 * 24
= 48
