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Question 422862: Find an equation of the line in the slope-intercept form containing the point (1,-5) and perpendicular to the line 2x+y = -4
Answer by tutorcecilia(2152)   (Show Source):
You can put this solution on YOUR website! Remember the rule that perpendicular lines have slopes that are the negative inverse of each other.
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First find the slope of the first line by getting the y-value to one side:
2x+y= -4
y= -2x -4
In the slope-intercept format, y = mx + b, where the m-value represents the slope, so the slope is -2.
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Secondly, the slope of the second perpendicular line is the "negative inverse" of the first slope, so:
-2 becomes 1/2 (flip the slope and multiply it by a negative 1 (-1)).
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Thirdly, plug-in the values for the second line and put them in the y=mx+b form:
x= 1; y=-5; and the slope m = 1/2, so, we need to solve for the b-value:
y=mx+b
-5 =(1/2)(1) + b
-5-(1/2) = b
b=-5.5, so
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The second line is y = (1/2) x + 4.5
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You should go back and check this by plugging in all of the values.
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