SOLUTION: At noon Maria left the neighborhood and headed for the theater on her bike. She pedaled 10 mph. At 2:00, her friend got a ride along the sanme route from her parent. The parent dro
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-> SOLUTION: At noon Maria left the neighborhood and headed for the theater on her bike. She pedaled 10 mph. At 2:00, her friend got a ride along the sanme route from her parent. The parent dro
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Question 422815: At noon Maria left the neighborhood and headed for the theater on her bike. She pedaled 10 mph. At 2:00, her friend got a ride along the sanme route from her parent. The parent drove 30 mph. How long did it take the car to catch up to Maria? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! At noon Maria left the neighborhood and headed for the theater on her bike. She pedaled 10 mph. At 2:00, her friend got a ride along the sanme route from her parent. The parent drove 30 mph. How long did it take the car to catch up to Maria?
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Maria DATA:
rate = 10 mph ; time = x hrs ; distance = rt = 10x miles
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Friend DATA:
rate = 30 mph ; time = x-2 hrs ; distance = rt = 30(x-2) miles
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Equation:
10x = 30(x-2)
10x = 30x-60
20x = 60
x = 3 hrs (catch-up time)
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Cheers,
Stan H.
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