Question 422805: The length of a rectangular room is 4 feet longer than twice the width. If the room's perimeter is 200 feet, what are the room's dimensions?
Answer by algebrahouse.com(1659)   (Show Source):
You can put this solution on YOUR website! "The length of a rectangular room is 4 feet longer than twice the width. If the room's perimeter is 200 feet, what are the room's dimensions?"
x = width
2x + 4 = length {length is 4 longer than twice width}
Perimeter of a rectangle = 2(width) + 2(length)
2x + 2(2x + 4) = 200 {perimeter is 2(width) + 2(length)}
2x + 4x + 8 = 200 {used distributive property}
6x + 8 = 200 {combined like terms}
6x = 192 {subtracted 8 from both sides}
x = 32 {divided both sides by 6}
2x + 4 = 68 {substituted 32, in for x, into 2x + 4}
width = 32ft and length = 68ft
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