SOLUTION: Write the equation of the line parallel to {{{3x-y=2}}} and passing through (2,-3). Someone PLEASE help me!!

Click here to see ALL problems on Expressions-with-variables

Question 42280: Write the equation of the line parallel to and passing through (2,-3). Someone PLEASE help me!!
Found 2 solutions by psbhowmick, fractalier:
Answer by psbhowmick(878) (Show Source):
You can put this solution on YOUR website!
The line 3x - y = 2 in slope intercept form is y = 3x - 2.
Hence its slope = 3.
So the line parallel to it must also have slope = 3.
Let its equation in slope intercept form be y = 3x + c_____(1).
This line has to pass through (2,-3).
So x = 2 and y = -3 must satisfy the equation (1) of the line.
Substituting x = 2, y = -3 in (1) we have

or c = -9
Putting this value of c in (1) we obtain the reqd. equation to the st. line as
y = 3x - 9.

Answer by fractalier(6550) (Show Source):
You can put this solution on YOUR website!
If it's parallel to 3x - y = 2, it has the same slope...
The slope of 3x - y = 2 can be found from y = 3x - 2...the slope is 3.
Now use the slope-intercept form and lug in...we get
y - y1 = m(x - x1)
y + 3 = 3(x - 2)
y + 3 = 3x - 6
y = 3x - 9