You can put this solution on YOUR website! a rectangle has length (x-3)squared and width 4. the perimeter of the rectangle is 40. find the length.
Sol'n:
P = 2w + 2L
L = x-3
W = 4
P = 40
40 = 2(4) + 2(x-3)
40-8 = 2x - 6
38 = 2x
x = 19
thus,
L = 19-3
L = 16 units ----answer
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