SOLUTION: Joan is the owner of Starbucks. She has many varieties of coffee in the shop including a Kona variety that sells for $6.20 per pound and an amaretto coffee that sells for $5.80 a
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Question 42256This question is from textbook
: Joan is the owner of Starbucks. She has many varieties of coffee in the shop including a Kona variety that sells for $6.20 per pound and an amaretto coffee that sells for $5.80 a pound. She finds that by mixing these two blends she creates a coffee that sells well. If she uses 18 pounds of amaretto coffee in the blend and wishes to sell the mixture at $6.10 per pound, how many pounds of the Kona coffee should she mix with the amaretto coffee? This question is from textbook
You can put this solution on YOUR website! Let k be the amount of Kona and a be the amount of amaretto.
The setup looks like this:
6.20k + 5.80a = 6.10(k+a)
6.20k + 5.80(18) = 6.10(k + 18)
620k + 580(18) = 610(k + 18)
620k + 10440 = 610k + 10980
10k = 540
k = 54 pounds
