SOLUTION: Find all -intercepts and -intercepts of the graph of the function. f(x)=-x^3+x^2+12x If there is more than one answer, separate them with commas.

Algebra ->  Rational-functions -> SOLUTION: Find all -intercepts and -intercepts of the graph of the function. f(x)=-x^3+x^2+12x If there is more than one answer, separate them with commas.       Log On


   

Question 422556: Find all -intercepts and -intercepts of the graph of the function.
f(x)=-x^3+x^2+12x
If there is more than one answer, separate them with commas.

Found 2 solutions by MathLover1, lwsshak3:
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

f%28x%29=-x%5E3%2Bx%5E2%2B12x or y=-x%5E3%2Bx%5E2%2B12x
y=-x%28x%5E2-x-12%29...replace -x with 3x-4x
y=-x%28x%5E2%2B3x-4x-12%29
y=-x%28%28x%5E2%2B3x%29-%284x%2B12%29%29
y=-x%28x%28x%2B3%29-4%28x%2B3%29%29
y=-x%28x-4%29%28x%2B3%29
set y=0 and find solutions
-x%28x-4%29%28x%2B3%29=0
first solution is x=0
second solution is x-4=0.....->...x=4
third solution is x%2B3=0.....->...x=-3


Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Find all -intercepts and -intercepts of the graph of the function.
f(x)=-x^3+x^2+12x
..
f(x)=-x^3+x^2+12x
=-x(x^2-x-12)
0=-x(x-4)(x-3)
y-intercept
x=0
y=0
..
x-intercept
y=0
x=0,4,3
The graph below is a check of the intercepts obtained above:
..
+graph%28+300%2C+300%2C+-5%2C+10%2C+-10%2C+10%2C+-x%2A%28x-4%29%2A%28x-3%29%0D%0A%29+