SOLUTION: Solve log(2) (7x-3)>or=log(2) (x+12). Thank you

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Question 42255: Solve log(2) (7x-3)>or=log(2) (x+12).
Thank you
Answer by fractalier(6550) About Me  (Show Source):
You can put this solution on YOUR website!
If log(2) (7x-3) ≥ log(2) (x+12),
then
(7x-3) ≥ (x+12)
and
6x ≥ 15
x ≥ 5/2